13x^2+54x=55

Solution for 13x^2+54x=55 equation:

13x^2+54x=55

We move all terms to the left:

13x^2+54x-(55)=0

a = 13; b = 54; c = -55;
Δ = b2-4ac
Δ = 542-4·13·(-55)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-76}{2*13}=\frac{-130}{26}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+76}{2*13}=\frac{22}{26}
=11/13
$